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recti
músculo recto mayor del abdomen

star faller
(180 + 170 ) * n (1 + 1) * n 350 * n 2*n then we can remove "n", which is in the numerator and the denominator at the same time, and obtain that the joint average size of the officers' class is: 350 / 2 = 175 cm anyway, there is a faster procedure that we should employ here, instead of the previous formula with the unknown "n", just using our numerical reasoning: if there are as many men as women in this class, and we know their respective average sizes (180 and 170 cm), then the average for the whole group (no matter if there are 100 women and 100 men, or just 1 woman and 1 man) has to be necessarily the direct average between both figures: (180 + 170) / 2 = 175 cm moreover, you can use the valuable help of the chart here, because we could visually deduce that the average between the two bars in class for officers, men (180 cm) and women (170 cm), has to be in the middle point between them, which is 175 cm. next we go to analyse the class for nco. initially, we could use the general formula, now supposing that the number of men is "m" and the number of women is "w" (because they are different in this class). 105

diastasis recti
diástasis del recto anterior del abdomen

diastasis recti abdominis
diástasis del recto anterior del abdomen

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