Sie suchten nach: mujhe maaf kar do (Hindi - Italienisch)

ab dono taraf 10 guna kar do.
quindi moltiplichiamo entrambi i lati di questa equazione per 10.

problem 70 vo chahte hain ham practise kartein rahein to vo liktein hai x^2+8x+16,over x+3 divided by 2x plus 8, over x squared minus 9 to jab tum ek fraction se divide karte hai to tum us fraction ke inverse se multiply kar dete ho to ye barabar hai x squared plus 8x plus + sixteen (x^2+8x+16) over x plus three (x+3) time eska ulta(inverse), x squared minus nine (x^2-9) over 2x plus eight (2x+8) . chalo ab ese ham simplify kartein hain . to ye ,4 plus 4 is 8 hai, or ye 4 times 4 is 16 hai. to ham ese ase likh saktein hai x plus 4 times x plus 4.....(x+4)(x+4) to ham ese ase likh saktein hai x plus 4 times x plus 4.....(x+4)(x+4) x squared minus 9... a squared minus b squared.. (a^2-b^2) ke form mein hai to ye hua (x+3)(x-3)...x plus 3 times x minus 3 . ham edhar 2 bahar nikal saktein hai. to ye ban jayega 2(x+4) .. 2 times x plus 4 hamare par edhar x+3 hai or han jab ham fractions multiply kartein hain ham bhas sare numerators ko multiply kar dete hain over sare denominators ko multiply kar dete hai to tum edhar ek line bana dete ho to numerator (x+4)(x+4)(x+3)(x-3)...x plus 4 times x plus 4 times x plus 3 times x minus 3 hua to numerator (x+4)(x+4)(x+3)(x-3)...x plus 4 times x plus 4 times x plus 3 times x minus 3 hua ye sab divided by (x+3)(2x+4)..x plus 3 times 2 times x plus 4 to ab thodi cancellation kartein hain ye hi to maze vali bat hai to hamarein pas (x+4) or (x+4) hai, enhe cancel kardo to hamarein pas (x+4) or (x+4) hai, enhe cancel kardo hamarein pas (x+3) or (x+3) hai, enhe bhi cancel kar do hamarein pas (x+3) or (x+3) hai, enhe bhi cancel kar do or ab hamarein pas kya bachta hai hamarein pas bachta hai (x+4)(x-3) ye sab divided by 2 or choice c vala hai ab mein apkon next video mein milta hoon ab mein apkon next video mein milta hoon
problema 70. ragazzo, vogliono che ci confrontiamo con questo. e' un buon esercizio.