Sie suchten nach: go (Spanisch - Latein)

go
igo

it go
it eunt

eat and go
nihil prius manducare

i will go;
ego vado vos

and i will go
et ego vadam

go to joseph;
ite ad joseph

i will not go away
non recedam

so we go to the dark
sic itur ad tenebris

and go your way to safety
et vade viam tuam in salutem

let's go over to bethlehem
transeamus usque bethlehem et

leave all hope you who go in
relinquite omnem spem vos qui intratis

go, you cursed, into eternal fire
ite maledicti in ignem aeternum

go back! fortune favors the bold!
vade retro!audaces fortuna juvat!

which, however, i will go, i will
ego autem vadam quo

in which i will go: and what profit
quo vadam et ad quid

success to the power of the stars, so we go to the
macte virtute sic itur ad astra

lord, to whom shall we go? thou hast the words of eternal life
domine ad quem ibimus verba vitae aeternae habes

he proves that the wise man is not to go around the honors, but she also praises
non ambire probat sapiens sed laudat honores

then we can remove "n", which is in the numerator and the denominator at the same time, and obtain that the joint average size of the officers' class is: 350 / 2 = 175 cm anyway, there is a faster procedure that we should employ here, instead of the previous formula with the unknown "n", just using our numerical reasoning: if there are as many men as women in this class, and we know their respective average sizes (180 and 170 cm), then the average for the whole group (no matter if there are 100 women and 100 men, or just 1 woman and 1 man) has to be necessarily the direct average between both figures: (180 + 170) / 2 = 175 cm moreover, you can use the valuable help of the chart here, because we could visually deduce that the average between the two bars in class for officers, men (180 cm) and women (170 cm), has to be in the middle point between them, which is 175 cm. next we go to analyse the class for nco. initially, we could use the general formula, now supposing that the number of men is "m" and the number of women is "w" (because they are different in this class). 105
(180 + 170 ) * n (1 + 1) * n 350 * n 2*n then we can remove "n", which is in the numerator and the denominator at the same time, and obtain that the joint average size of the officers' class is: 350 / 2 = 175 cm anyway, there is a faster procedure that we should employ here, instead of the previous formula with the unknown "n", just using our numerical reasoning: if there are as many men as women in this class, and we know their respective average sizes (180 and 170 cm), then the average for the whole group (no matter if there are 100 women and 100 men, or just 1 woman and 1 man) has to be necessarily the direct average between both figures: (180 + 170) / 2 = 175 cm moreover, you can use the valuable help of the chart here, because we could visually deduce that the average between the two bars in class for officers, men (180 cm) and women (170 cm), has to be in the middle point between them, which is 175 cm. next we go to analyse the class for nco. initially, we could use the general formula, now supposing that the number of men is "m" and the number of women is "w" (because they are different in this class). 105