From professional translators, enterprises, web pages and freely available translation repositories.
def.:
定义 :
Last Update: 2011-10-23
Usage Frequency: 3
Quality:
priority def
优先级定义
Last Update: 2006-11-24
Usage Frequency: 5
Quality:
def&ragment using vss defragmentation method (recommended)
使用 vss 方法进行碎片整理(推荐)(&f)
Last Update: 2007-11-09
Usage Frequency: 4
Quality:
Reference:
Warning: Contains invisible HTML formatting
violence experienced by indigenous women and girls "def[ies] simple categorisation ".
暴力侵害土著妇女和女孩的行为往往 "难以加以简单的分类 "。
Last Update: 2016-12-04
Usage Frequency: 1
Quality:
Reference:
Warning: Contains invisible HTML formatting
"muhammad def, who is responsible for the february-march 1996 attacks, is running free in the gaza strip ...
"要对1996年2月-3月的袭击负责的穆罕默德·德夫在加沙地带出入自由...。
Last Update: 2016-12-04
Usage Frequency: 1
Quality:
Reference:
Warning: Contains invisible HTML formatting
you can control a kig construction by means of a "pykig" python script, that can be executed with the command pykig. py. here is a nice example (hexagons. kpy) you can try: kigdocument. hideobjects() def hexagons (c, v, n): hexagon = polygonbcv (c, v, 6) if n & lt; = 0: hexagon. show() for i in range(6): polygonside (hexagon, i, true) return cnew = midpoints (c, v) hexagons (cnew, v, n-1) for k in [2,4]: v1 = polygonvertex (hexagon, k) cnew = midpoints (c, v1) hexagons (cnew, v1, n-1) hexagons (point(0,0), point(1,0), 5)
您可以使用“ pykig” 这个 python 脚本来控制 kig 的构造, 您只要执行这个命令即可: pykig. py。 这里有个不错的例子 (hexagons. kpy) 您可以试试 : kigdocument. hideobjects () def hexagons (c, v, n): hexagon = polygonbcv (c, v, 6) if n & lt; = 0: hexagon. show () for i in range( 6): polygonside (hexagon, i, true) return cnew = midpoints (c, v) hexagons (cnew, v, n- 1) for k in [2, 4]: v1 = polygonvertex (hexagon, k) cnew = midpoints (c, v1) hexagons (cnew, v1, n- 1) hexagons (point( 0, 0), point( 1, 0), 5)
Last Update: 2011-10-23
Usage Frequency: 3
Quality:
Reference:
Warning: Contains invisible HTML formatting