Results for sove lanmou translation from French to English

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sove lanmou

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French

lanmou mwen

English

Last Update: 2024-03-09
Usage Frequency: 1
Quality:

French

ou se sèl lanmou mwen ak tout lavi mwen/tu es mon seul amour et toute ma vie

English

your are my only love and my whole

Last Update: 2023-06-14
Usage Frequency: 1
Quality:

French

jody a se fèt w pitit mwen mwen renmenw anpil rose se ou ki fèm santim map viv se w ki fèm konn gou lanmou rose

English

jody a se fèt w pitit mwen mwen renmenw anpil rose se or ki fèm santim map viv se w ki fèm konn gou lanmou rose

Last Update: 2021-08-21
Usage Frequency: 1
Quality:

Reference: Anonymous

French

lanmou l'amour c'est ce que vous faites/l’amour est ce que vous faites

English

love is what you do

Last Update: 2023-09-26
Usage Frequency: 1
Quality:

Reference: Anonymous

French

lanmou pa janm fè m mal li geri/renmen pa janm fè mwen mal li geri/l'amour ne me fait jamais de mal il guérit

English

love never hurts me it heals

Last Update: 2019-09-25
Usage Frequency: 1
Quality:

Reference: Anonymous

French

renmen ou se idantite mwen /renmen ou, se idantite mwen /lanmou ou se tout idantite'm/ton amour est mon identité

English

your love is my identity

Last Update: 2019-01-16
Usage Frequency: 3
Quality:

Reference: Anonymous

French

en ce qui concerne l'algorithme de type sove, on suppose qu'à toute section n e [l,τ], à chaque sous-état de départ s'ev n _ j sont associes : • une liste ordonnée jμ^_ j ω (s'),ωe [l,Ω]j des Ω meilleures métriques accumulées de sous-états en récursion avant ; " une liste ordonnée jltn-θ-l ω •* ω e [l>Ω]) des Ω trajets survivants correspondants fi n i= _ n 1 -Θ-1 s ω' - - !

English

[0138] as far as the sove type algorithm is concerned, it is assumed that at any section n ε [1, τ], with each departure substate s′εv n−1 {circle over (×)} are associated: [0139] an ordered list {u n−1,ω → (s′),ωε[1,Ω]} of the Ω best accumulated metrics of substates during forward recursion; [0140] an ordered list { û i=n−θ−1 ω n−1 s′ ,ωε[1,Ω]} of the Ω corresponding survivor paths û i=n−θ−1ω n−1 s′ ={ û n−θ−1 ω s′ , û n−θω s′ , . . . , û n−1 ω s′ } [0141] terminating at s′.

Last Update: 2014-12-03
Usage Frequency: 1
Quality:

Reference: Anonymous
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