Usted buscó: foo bar (Inglés - Alemán)

foo($bar);
foo($bar);

echo $foo[bar];
echo $foo[bar];

//$ void foo( int bar )
//$ void foo( int bar )

echo $arr["foo"]; // bar
echo $arr["foo"]; // bar

$foo =& find_var($bar);
$foo =& find_var ($bar);

$foo[bar] = 'enemy';
$foo[bar] = 'feind';

'example', 'foo', 'bar' );
classkit_method_copy('bar', 'baz', 'foo', 'example');

echo $foo,$bar;// foobarbarbaz
echo $foo,$bar;// foobarbarbaz

ns::foo a = foo(bar);
a a(42), b(23);

$bar = each($foo);
$bar = each ($foo);

$this->addformfields('foo','bar');
$update -> setcontext ( 'projectone' );

before: foo! after: bar!
foo!

assert (myfunction (foo, bar) > 0)
assert (meinefunktion (foo, bar) > 0)

arr.add(new tuple2(foo, bar));
arr.add(new tuple2(foo, bar));

the syntax is -o foo::bar=bar.
die syntax lautet -o foo::bar=bar.

end of my long comment */ foo = "bar";
ende meines langen kommentars */ foo = "bar";

$bar = &$foo;// reference $foo via $bar.
$bar = &$foo;// zeiger auf $foo in $bar erzeugen.

you cannot even type `cvs add foo/bar'!
sogar `cvs add foo/bar' wird nicht funktionieren!

$file -> setname ( '/foo/bar/baz.txt' );
$this -> setplaceholder ( 'namedesplatzhalters' , $htmloutput );

now, i am printing some {$foo->bar[1]}.
nun schreibe ich gerade einige {$foo->bar[1]}.