Hai cercato la traduzione di python matplotlib secondary y axis da Spagnolo a Inglese

tome los retos y deje que polygon, tessellation, exponent, tangent y axis le ayuden a resolverlos.
take one of the challenges, and let polygon, tessellation, exponent, tangent, and axis help you solve them.

la malformación de los huesos occipital - atlas y axis (las vértebras cervicales primera y segunda en la base del cráneo):
malformation of the occipital bones – atlas and axis (the first and second cervical vertebrae at the base of the skull):

entre los mamíferos de esta zona se destacan los hurones, gatos monteses, gatos de pajonal, comadrejas overas y coloradas, ciervos colorados y axis estos últimos introducidos en la zona.
the following mammals inhabit this area: ferrets, wildcats, pampas cats, large american and thick-tailed opossums, red and axis deer –the latter have been introduced in the area by man.

los inversores que han entrado en el capital son kurma life sciences partners, idinvest funds, boehringer ingelheim venture fund, caixa capital risc, además de ysios capital y axis que ya participaron en la primera ronda de financiación.
the investors that have joined the equity holders of this catalan company are kurma life sciences partners, idinvest funds, boehringer ingelheim venture fund and caixa capital risc, in addition to ysios capital and axis, which also participated in the first round of funding.

dejar x ser el punto mediano del anuncio. tomar a coordenadas con origen el punto mediano de a.c., el x-axis a lo largo de a.c. y el y-axis a través del a. es suficiente demostrar que y-coordina de suma de o y de o a el de a, o equivalente que su medio es iguales que y-coordinan del x. pero es fácil ver que x-coordinar de x que el de los iguales de o x-coordina menos de o menos que del x. por lo tanto y-coordinar las diferencias debe también ser igual
let x be the midpoint of ad. take coordinates with origin the midpoint of bc, x-axis along bc and y-axis through a. it is sufficient to show that the y-coordinates of o and o' sum to that of a, or equivalently that their mean is the same as the y-coordinate of x. but it is easy to see that the x-coordinate of x less that of o equals the x-coordinate of o' less that of x. hence the y-coordinate differences must also be equal