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annex 2, figure 12, to this regulation gives examples of arrangements of approval marks relating to the above case.
i bilag 2, fig. 12 i dette regulativ er givet eksempler på godkendelsesmærkets sammensætning i forbindelse med ovennævnte tilfælde.
vacacionesincidence category: examples: anniversary of historical or personal event; big date; remembrance, etc
ferieincidence category: examples: anniversary of historical or personal event; big date; remembrance, etc
qué estaba haciendo cuando la aplicación « %1 » falló@info examples about information the user can provide
hvad jeg gjorde da programmet "% 1" brød sammen@ info examples about information the user can provide
modo de vista de archivos, preferencias de agrupación, ordenación y vista previa, y carpeta que estaba explorando. @info examples about information the user can provide
filvisningstilstand, indstilling af sortering og gruppering, indstilling af forhåndsvisning og mapper du browsede. @ info examples about information the user can provide
tipos de medios (extensión y formato) que estuve viendo y/ o escuchando. @label examples about information the user can provide
medietype (filendelse og format) du så og/ eller lyttede til. @ label examples about information the user can provide
the main issue in this exercise is to know how to use the "double rule of three", that you have already seen here, in case something similar may appear in your tests. on the other hand, to save time in finding the rig t answer, if your alternatives were a bit more complicated, for example: a) it is 15% higher than the rent on martina's apartment. b) it is 45% higher than the rent on martina's apartment. c) it is 65% higher than the rent on martina's apartment. d) it is 85% higher than the rent on martina's apartment. e) none of the above statements is correct. i would recommend calculating first the weight of klaus' rent on martina's rent, simply by dividing them: 1800 / 900 = 2 this means, 1 + 1, or 100% + 100%, so 100% increase. or let us imagine that the two rents were 1200 and 900, then: 1200 / 900 = 1.33 this means, 1 + 0.33, or 100% + 33%, so 33% increase. this way, you are able to quickly match the real increase against the answer options, without having to calculate the increase proposed in every option. 84
we must compare it with the rent on martina's apartment. moreover, we find a last option "none of the above statements is correct", forcing us to check, one by one, if any of them is right. let us do it: a) it is half the rent on martina's apartment. is the rent on klaus' apartment (1800 euros) half the rent on martina's apartment (900 euros)? obviously not - it is double the rent, in fact. b) it is 100 euros less than the rent on martinapartment. again incorrect - it is 900 euros higher than the rent on martina's apartment. c) it is 50% higher than the rent on martina's apartment. here we should increase 50% the rent on martina's apartment to check if this is right. so: 900 * (1 + 0. 5) = 900 * 1.5 = 1350 or if you prefer working with percentages: 900 + (900 * 50%) = 1350 we can see that 1800 is much higher than martina's rent increased 50%, so it is incorrect too. d) it is 100% higher than the rent on martina's apartment. we may increase 100% the rent on martina's apartment to check if this is right. increasing 100% any value means to double it (that is, multiplying by 2), but still you can follow our usual method to ensure: 900 * (1 + 1) = 900 * 2 = 1800 or working with percentages: 900 + (900 * 100%) = 1800 we can see that 1800 is exactly martina's rent increased 100%, so the right answer is option d). 83
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