Você procurou por: two numbers both greater than 29 (Espanhol - Inglês)

no greater than 5%
no mayor al 5%

greater than 10 000 000
greater than 10 000 000

we were greater than that.
we were greater than that.

it consists of hydrocarbons having carbon numbers predominantly greater than c5.]
it consists of hydrocarbons having carbon numbers predominantly greater than c5.]

it consists of hydrocarbons having carbon numbers predominantly greater than c5.]
it consists of hydrocarbons having carbon numbers predominantly greater than c5.]

the sum is greater than its parts, that is all.
the sum is greater than its parts, that is all.

for ranks greater than two, the symmetric or antisymmetric index pairs must be explicitly identified.
for ranks greater than two, the symmetric or antisymmetric index pairs must be explicitly identified.

the maicoletta had a top speed of greater than 70mph, comparable with most 250cc motorcycles of the time.
the maicoletta had a top speed of greater than 70 mph, comparable with most 250cc motorcycles of the time.

it consists predominantly of aromatic hydrocarbons having carbon numbers greater than c5 and boiling above approximately 40 °c (104 °f).]
it consists predominantly of aromatic hydrocarbons having carbon numbers greater than c5 and boiling above approximately 40 °c (104 °f).]

it consists predominantly of aromatic hydrocarbons having carbon numbers greater than c5 and boiling above approximately 40 °c (104 °f).]
it consists predominantly of aromatic hydrocarbons having carbon numbers greater than c5 and boiling above approximately 40 °c (104 °f).]

[a complex combination of hydrocarbons obtained by the distillation of the products of steam cracking or similar processes after taking off the very light products resulting in a residue starting with hydrocarbons having carbon numbers greater than c5.
[a complex combination of hydrocarbons obtained by the distillation of the products of steam cracking or similar processes after taking off the very light products resulting in a residue starting with hydrocarbons having carbon numbers greater than c5.

[a complex combination of hydrocarbons obtained by the distillation of the products of steam cracking or similar processes after taking off the very light products resulting in a residue starting with hydrocarbons having carbon numbers greater than c5.
[a complex combination of hydrocarbons obtained by the distillation of the products of steam cracking or similar processes after taking off the very light products resulting in a residue starting with hydrocarbons having carbon numbers greater than c5.

first determine if "m" is indeed greater than 1.0 by calculating "m" from the subsonic equation.
it is first determined whether m is indeed greater than 1.0 by calculating m from the subsonic equation.

modeling work has shown that it is possible for local areas at elevations greater than 300–500 meters to contain year-round snow cover even with high atmospheric co2 concentrations.
modeling work has shown that it is possible for local areas at elevations greater than 300–500 meters to contain year-round snow cover even with high atmospheric concentrations.

la opción ge (greater than, mayor que), al igual que le, aplicará la coincidencia si el prefijo es mayor o igual al prefijo especificado en la lista.
less than or equal to prefix numbers and greater than or equal to prefix numbers can be used together.

if "m" is greater than 1.0 at that point, then use the value of "m" from the subsonic equation as the initial condition in the supersonic equation.
if m is greater than 1.0 at that point, then the value of m from the subsonic equation is used as the initial condition in the supersonic equation.

[the volatile organic liquid extracted from the gas evolved in the high temperature (greater than 700 °c (1292 °f)) destructive distillation of coal.
[the volatile organic liquid extracted from the gas evolved in the high temperature (greater than 700 °c (1292 °f)) destructive distillation of coal.

contenedor no incluidohere, overload is used as a programming term. this string is used to display how many overloaded versions there are of the function whose name is the second argument. the numeric argument is always greater than one, so translation of the singular case is only necessary in languages where the singular form is used for 21, 31 etc.
not included container

and if it is a percentage of decrease, we will subtract: 80 - 20 = 60, so we will obtain that 80 decreased by 25% is 60. knowing this, we should point out that there is a shortcut to do these operations, which may help us (a lot!) to speed up our calculations. we can use the reference to the unit (1) instead of the traditional 100%, so, to increase a number by 25%, we add: 1 + 0.25 = 1.25 (mentally, so we save time) and then we apply it to our initial amount: 80 * 1.25 = 100 getting the same result above mentioned but in only one arithmetical operation (one multiplication). in the same way, to decrease a number by 25%, we subtract: 1 - 0.25 = 0.75 (mentally again) and again we apply it to our initial amount: 80 * 0.75 = 60 using this method, you will save valuable time, reducing the operations that you have to perform and, sometimes, your need of the calculator. i recommend starting with 'easy' percentages and round numbers, both multiplying and dividing (you can use the calculator when you need it), to see for yourself their effect on the figures. for example: to increase and decrease 200 by 25% 200 * 1.25 = 250 200 * 0.75 = 150 10
to increase and decrease 500 by 40% 500 * 1.40 = 700 500 * 0.60 = 300 to increase and decrease 300 by 30% 300 * 1.30 = 390 300 * 0.70 = 210 so, as you can see, when multiplying by more than the unit (1), we increase the initial number, and, on the contrary, when multiplying by less than the unit, we decrease the initial number. as you get used to practise this shortcut, you will feel more comfortable to do it with different and longer decimals. for example, to increase by 1%, we can multiply by 1.01 (i.e., 1 + 0.01); and to increase by 0.5%, we can multiply by 1.005 (i.e., 1 + 0.005). with the same idea, to decrease by 1%, we can multiply by 0.99 (because it is 1 - 0.01); and to decrease by 0.5%, we can multiply by 0.995 (because it is 1 - 0.005). here we present some examples: increasing 200 by 1% 200 * 1.01 = 202