You searched for: hamein (Hindi - Engelska)

hamein in baato pe amal karna
hamein in baato pe amal karnae

take hamein future me preshani na ho
take hamein future me preshani na ho

allah hamein nimaaz parhny ki tofeeq dy
allah hamein nimaaz parhny ki tofeeq dy

hamein behtreen taleem o tarbiyat di ja rahi h
hamein behtreen taleem o tarbiyat di ja rahi h

ek mahina pura ho gya hamein baat karty huy or mujhy sab buhat acha lagta ha os k sy baat kar k pata ni mera dil krta ha mein os sy batein karti rahun sb chor kr
ek mahina pura ho gya hamein baat karty huy or mujhy sab buhat acha lagta ha os k sy baat kar k pata ni mera dil krta ha mein os sy batein karti rahun sb chor kr

liye ek counterexample hai to, ek counterexample, ek udharan jo dikhata hai ki ye kathan hamesha sach nahi hota to kathan ye hai ki sare positive integers do ya teen dwaravibhajye hain to hamein yahi positive integer dhoondna jo na do na hi teen se vibhajye ho sau do dwaravibhajye hai na?
so, a counterexample, an example that shows that this isn't always true. so the statement is all positive integers are divisible by 2 or 3. so we just have to find a positive integer that is not divisible by 2 or 3, by neither 2 nor 3.

ye (z+1) en mein se koi (z+1) ko cancel out kar dega mein esse cancel kar deta hoon ye 'z' es 'z' ko cancel out kardega or ab hamare pas kya bachta hai sab ab simplify ho gaya hai 7(z-6) over 4(z+1) mein ha ha oh maine edhar (z-b) likh diya ye to (z+2)(z-2) hai vo sab (a^2-b^2) = (a-b)(a+b) mein maine galti kar di (z^2-4) = (z+2)(z-2) hot hai na ki z-b, mujhe laga ye 6 tha to yeh (z-2) hai or yeh (z-2) hai to sahi choice 1 hai galti ke liye sorry . ok, vo ab chahatein ki ab ham ye sab vapas karein vo ab chahatein ki ab ham product find karein (x+5) over (3x+2) times (2x-3) over (x-5) yahan pe ham jyada kuch simplification nahi kar saktein hain hamein bas multiply karna hoga to ye barabar hoga (x+5)(2x-3) divided by 3x mein bas numerator ko multiply kar raha hoon or fir denominator ko multiply kar raha hoon -- ( 3x+2)(x-5) or ham ab dono binomial ko multiply kar dete hain, x*2x = 2x^2 x*(-3) = -3x 5*2x=10x 5*(-3)=(-15) . ab ham denominator ko multiply karte hain 3x*x = 3x^2 3x*(-5) = 15x 2*x = 2x 2*(-5)=(-10) or ab dektein hain ki ham simplify kar saktein hai ya nahi numerator ko dekho 2x^2
this z plus 1 cancels out with one of these z plus 1's. i'll do the one that's written messier. and let's see, this z cancels out with this z.