Şunu aradınız:: bharosa hai (Hintçe - İngilizce)

khud par bharosa hai
khud par bharosa karo

mout ka bharosa nahi hai
mout ka bharosa nahi hai

humpe bharosa nahin hai
humpe bharosa nahin hai

mujhe apne aap par bharosa hai
i am sure you are here

◦•●◉✿kya aapko mujhpe bharosa hai✿◉●•◦
•●◉✿kya aapko mujhpe bharosa hai✿◉●•◦

kya tum ko mujh par bharosa nahi hai
kya tum ko mujh par bharosa nahi hai

kya tumhe khud par bharosa nahin hai
kya tumhe khud par bharosa nahin hai

mujhe bharosa karne mai mushkil hoti hai
mujhe bharosa karne mai mushkil hoti hai

kisi ka bharosa pane ke liey khud ko khona parts hai
kisi ka bharosa pane ke liey khud ko khona parts hai

mere galti hai maine bharosa kiya
mere galti hai maine bharosa kiya

mujhe apne aap par bharosa hai hi nhi dusro pe kya hi kru
mujhe apne aap par bharosa hai hi nhi dusro pe kya hi kru

muje pura bharosa hai ki aap is competition me aage tak jaoge
muje pura yakin hai ki aap is competition me aage tak jaoge

muze bharosa nahi ho raha hai ki etni cute girl se mai bat kar raha hu
muze bharosa nahi ho raha hai ki etni cute girl se mai bat kar raha hu

mujhe tum par bharosa nhi hai tum kabhi bhi apni bat sa mukar jaatay hu
mujhe tum par bharosa nhi hai tum kabhi bhi apni bat sa mukar jaatay hu

mujhe sirf allah pe bharosa hai aur khud pe yakeen zindagi asaan ho jayegi
i only believe in allah.

ha mujhe malum hai kyoki khud se jyada mujhe aap pr bharosa hai ka english meaningi
ha mujhe malum hai kyoki khud se jyada mujhe aap pr bharosa hai ka english meaningi

sb matlabi hai kisi par bharosa nahi karna chahiye aj k zamane m
sb matlabi hai kisi par bharosa nahi karna chahiye aj k zamane m

mujhe abhi to pata nahin hai ki woh kya hai lekin hum usey 'e to the x' ke maclaurin representation me dalthe hain aur kyunki aapko mere par bharosa hai ki woh 'e of x' ke samaan hai aur uske sab derivatives jo 'e to the x' ke sab derivatives ke samaan hai jahaan x 0 ke samaan hai
well, i don't know what that is but we know we could put that into the maclaurin representation of e to the x and actually, since you're taking my leap of faith, that that is equal to e of x and all of its derivatives are equal to e to the x's derivatives at x equals 0, it's not that hard to imagine.