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caput 1
capitulo l
最后更新： 2022-08-01
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psalm 23:1
salmo 23:1
最后更新： 2022-01-18
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ecce romani 1
rome 1
最后更新： 2014-12-18
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of" from "1 of 19
página actual (alt+p)of" from "1 of 19
最后更新： 2014-08-20
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1" (msgctxt: "panel:showusername
proteja su equipo del uso no autorizado1" (msgctxt: "panel:showusername
最后更新： 2014-08-20
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mt 1:25: "et non cognoscebat eam donec"
y ella dio a luz a un hijo
最后更新： 2021-10-25
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1. demitto-is-ere, misi, missum
la gran diosa
最后更新： 2021-03-24
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1. pompeius post paucis diebus in thessaliam pervenit
hay frutos maduros
最后更新： 2021-04-04
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1" (msgctxt: "panel:showusername") to "1
11" (msgctxt: "panel:showusername") to "1
最后更新： 2014-08-20
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1. o domina caeli mundique regina, janua per quam omnes in imperium intrant
1. o domina caeli mundique regina, janua per quam omnes in imperium intrant
最后更新： 2020-12-13
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(180 + 170 ) * n (1 + 1) * n 350 * n 2*n then we can remove "n", which is in the numerator and the denominator at the same time, and obtain that the joint average size of the officers' class is: 350 / 2 = 175 cm anyway, there is a faster procedure that we should employ here, instead of the previous formula with the unknown "n", just using our numerical reasoning: if there are as many men as women in this class, and we know their respective average sizes (180 and 170 cm), then the average for the whole group (no matter if there are 100 women and 100 men, or just 1 woman and 1 man) has to be necessarily the direct average between both figures: (180 + 170) / 2 = 175 cm moreover, you can use the valuable help of the chart here, because we could visually deduce that the average between the two bars in class for officers, men (180 cm) and women (170 cm), has to be in the middle point between them, which is 175 cm. next we go to analyse the class for nco. initially, we could use the general formula, now supposing that the number of men is "m" and the number of women is "w" (because they are different in this class). 105
最后更新： 2021-03-16
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